By poker_boy | No Comments
Last updated: Thursday, July 14, 2011 | 78 Views Tags: 4400, blinds, chips, math, odds, poker, pot, there some kind
Another poker question has come in this week. Let’s tackle it straight away:
I’m trying to figure out how much a person has to raise all-in for me to be receiving pot odds of 2-to-1, 1.9-to-1, 1.8-to-1, etc, all the way down to 1.1-to-1.
For example, if someone raises all-in for 4400 chips, the pot is now 6800 and it’s costing me 3400 to call the 4400 raise as I’ve already posted the 1000 big blind, giving me pot odds of exactly 2-to-1 (6800-to-3400).
Is there some kind of formula I could use for this to work the rest out?
Thanks
Let the raise amount be x. Then the total pot is x+2400. The amount for you to call is x-1000. So we have r = (x+2400) / (x-1000). Solve for x:
rx - 1000r = x+2400,
x*(r-1) = 2400 + 1000r,
x = (2400+1000r) / (r-1).
Thus, for each r = 1.1, 1.2, …, 1.9, you can compute x.
Also, you can generalize the solution. Let the starting pot = p and big blind = b. Then the final solution is x = (p + b*r) / (r-1).
Mike Smith
