What Are the Chances of a Royal Flush and Four
By poker_boy | 5 CommentsLeave a Comment
Last updated: Friday, July 22, 2011 | 92 Views Tags: , , , , , , , ,

We’ve had a reader question come in on the subject of poker. Let’s take a look:

Question: Me and some of my friends were playing poker and it went down to just me and one of my mates.

In my hand I had two aces (Spade and Heart). My friend had a Jack (Clubs) and a 7 (irrelevant).

On the table there were another two aces (Club and Diamond). A King (Clubs). A Queen (Clubs) and a 10 (Clubs).

What are the chances?
The probability of getting a Royal Flush is ‘0.000154%’.

The probability of getting Four Aces is ‘0.0018%’.

Answer: It looks to me like we have to split this into parts and then add up the combinations. One player can have AA or just one A. The other player can have two cards to the royal or just one (if he only has one, the other player must have AA).

Case 1 — you get AA and he gets 2 royal flush cards (other than an Ace).
————–
(4 C 2) * 2(4 C 2) * 43 = 6*12*43 = 3096 combos

Case 2 — you get AA and he gets 1 card to a Royal.
———
(4C2) * (8 * 46) = 2208 combos

Case 3 — he gets 2 cards to a Royal and you get 1 ace
———-
4(4C2) * 44 = 24 * 44 = 1056 combos

Total combos = 3096 + 2208 + 1056 = 6360
Out of a possible: (52 C 2) * (50 C 2) * (48 C 5)

Probability = 1 in 437,324,057 <——-

Now, that’s just the probability that YOU get quad aces and HE gets a royal. I suppose the chance of either one of you getting the quads and royal is twice that, 2 out of 437324057. As for any two players in the game (you said you and some of your friends), it would be a little higher.

I usually check my work using a 2nd method but I don’t feel like it now. I’m about 85-90% sure I didn’t mess up, for what that’s worth :P

*Edit*
I’m pretty sure you can’t just multiply P(quad A) * P(royal), because they’re not independent probabilities.

Comments

5 comments
  1. Your Mamma
    July 22, 2011

    I’m not that good at math & statistics. Given that Royal Flush’s & 4 of a kind (outside of if you play with wilds or some weird game) are rare in and of themselves (even in 7 card games), seeing something like that has to be an extremely rare phenom.

    Leave a reply
  2. Gazza666
    July 22, 2011

    The chances are soooo high that i don’t believe what you’re saying

    Leave a reply
  3. Teehan Western
    July 22, 2011

    0.000154 times 0.0018 = 2.77200 × 10-7

    in simple english almost impossible

    Leave a reply
  4. Andrew
    July 22, 2011

    This actually happened in 2008 during the main event. It was one of the most talked about hands that year, so I’d be surprised if this wasn’t where you got the idea. The odds are 1 in 2.7 billion.

    Leave a reply
  5. Panda Bear
    July 22, 2011

    "in simple english almost impossible:

    And yet it happened at the world series of poker

    Leave a reply

Leave a Comment